CCNA (640-802) Lab – RIPv2 SIMULATOR

Central Florida Widgets recently installed a new router in their WinterPark office. Complete the network installation by performing the initial router configurations and configuring RIPV2 routing using the router command line interface (CLI) on the WinterPark router.

Configure the router per the following requirements:

Name of the router is WinterPark
Enable-secret password is te23lith
The password to access user EXEC mode using the console is Con231D
The password to allow telnet access to the router is toyo12ta
IPV4 addresses must be configured as follows:
Ethernet network 209.165.202.128/27 – router has last assignable host address in subnet
Serial network is 192.0.2.192/28 – router has last assignable host address in the subnet. Interfaces should be enabled.
Router protocol is RIP V2

Corrent Answer:

(1) Name the router:

Router>enable
Router#configure terminal
Router(config)#hostname WinterPark

(2) Set secret password:

WinterPark(config)#enable secret te23lith

(3) Set password for the console:

WinterPark(config)#line console 0
WinterPark(config-line)#password Con231D
WinterPark(config-line)#login
WinterPark(config-line)#exit

(4) Set the Telnet password:

WinterPark(config)#line vty 0 4
WinterPark(config-line)#password toyo12ta
WinterPark(config-line)#login
WinterPark(config-line)#exit

(5) Assign IP address for Ethernet interface (Fa0/0):

The Ethernet network 209.165.202.128/27 has:

Increment: 32 (/27 = 255.255.255.224 or 1111 1111.1111 1111.1111 1111.1110 0000)
Network address: 209.165.202.128
Broadcast address: 209.165.202.159 (because 128 + 32 – 1 = 159)

Therefore the last assignable host address in this subnet is 209.165.202.158 and we will assign it to Fa0/0 interface with these commands:

WinterPark(config)#interface fa0/0
WinterPark(config-if)#ip address 209.165.202.158 255.255.255.224
WinterPark(config-if)#no shutdown
WinterPark(config-if)#exit

(6) Assign IP address for Serial interface (S0/0/0):

Serial network 192.0.2.192/28 has:

Increment: 16 (/28 = 255.255.255.240 or 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.192
Broadcast address: 192.0.2.207 (because 192 + 16 – 1 = 207)

So the last assignable host address in this subnet is 192.0.2.207. Finally we assign it to s0/0/0 interface:

WinterPark(config)#interface s0/0/0
WinterPark(config-if)#ip address 192.0.2.207 255.255.255.240
WinterPark(config-if)#no shutdown
WinterPark(config-if)#exit

(7) Configure RIP v2 routing protocol:

WinterPark(config)#router rip
WinterPark(config-router)#version 2
WinterPark(config-router)#network 209.165.202.128
WinterPark(config-router)#network 192.0.2.207
WinterPark(config-router)#end
WinterPark#copy running-config startup-config

That's all.

CCNA (640-802) Lab – NAT SIMULATOR

A network associate is configuring a router for the CCNA Training company to provide internet access. The ISP has provided the company six public IP addresses of 198.18.184.105 198.18.184.110. The company has 14 hosts that need to access the internet simultaneously. The hosts in the CCNA Training company LAN have been assigned private space addresses in the range of 192.168.100.17 – 192.168.100.30.

The following have already been configured on the router:
– The basic router configuration
– The appropriate interfaces have been configured for NAT inside and NAT outside
– The appropriate static routes have also been configured (since the company will be a stub network, no routing protocol will be required.)
– All passwords have been temporarily set to "cisco"

The task is to complete the NAT configuration using all IP addresses assigned by the ISP to provide Internet access for the hosts in the Weaver LAN. Functionality can be tested by clicking on the host provided for testing.

Configuration information
  router name – Weaver
  inside global addresses – 198.18.184.105 198.18.184.110/29
  inside local addresses – 192.168.100.17 – 192.168.100.30/28
  number of inside hosts – 14

Correct Answer:

The CCNA Training company has 14 hosts that need to access the internet simultaneously but we just have 6 public IP addresses from 198.18.184.105 to 198.18.184.110/29. Therefore we have to use NAT overload (or PAT)

Double click on the Weaver router to open it

Router>enable
Router#configure terminal

First you should change the router's name to Weaver

Router(config)#hostname Weaver

Create a NAT pool of global addresses to be allocated with their netmask (/29 = 255.255.255.248). There were reports that the simulator in the real exam did not accept "prefix-length" keryword so you should use "netmask" keyword.

Weaver(config)#ip nat pool mypool 198.18.184.105 198.18.184.110 netmask 255.255.255.248

Create a standard access control list that permits the addresses that are to be translated

Weaver(config)#access-list 1 permit 192.168.100.16 0.0.0.15

Establish dynamic source translation, specifying the access list that was defined in the prior step

Weaver(config)#ip nat inside source list 1 pool mypool overload

This command translates all source addresses that pass access list 1, which means a source address from 192.168.100.17 to 192.168.100.30, into an address from the pool named mypool (the pool contains addresses from 198.18.184.105 to 198.18.184.110)

Overload keyword allows to map multiple IP addresses to a single registered IP address (many-to-one) by using different ports
The question said that appropriate interfaces have been configured for NAT inside and NAT outside statements.

This is how to configure the NAT inside and NAT outside, just for your understanding:

Weaver(config)#interface fa0/0
Weaver(config-if)#ip nat inside

Weaver(config-if)#exit

Weaver(config)#interface s0/0
Weaver(config-if)#ip nat outside
Weaver(config-if)#end

Finally, we should save all your work with the following command:

Weaver#copy running-config startup-config

Check your configuration by going to "Host for testing" and type:

C:\>ping 192.0.2.114

The ping should work well and you will be replied from 192.0.2.114

That’s all.